Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:
21 22 23 24 25
20 7 8 9 10
19 6 1 2 11
18 5 4 3 12
17 16 15 14 13
It can be verified that the sum of the numbers on the diagonals is 101.
What is the sum of the numbers on the diagonals in a 1001 by 1001 spiral formed in the same way?
My Solution
(defun Euler28(n)
(loop for i from 3 to n by 2
sum(let ((squarenum (* i i))
(tempnum (- i 1)))
(+ squarenum (- squarenum tempnum) (- squarenum (* 2 tempnum)) (- squarenum (* 3 tempnum))))))
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